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The resistance of a wire is Its length is increased by 10% by stretching. The new resistance will now be
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Correct option is A
In case of stretching of wire, R ∝ l2 ⇒ If length is increased by 10% resistance is increased by almost 20% Hence, new resistance R' = 10 + 20% of 10=10 +20100 × 10=12 ΩSimilar Questions
In an electrical cable there is a single wire of radius 9 mm of copper. Its resistance is 5Ω . The cable is replaced by 6 different insulated copper wires, the radius of each wire is 3 mm . Now the total resistance of the cable will be
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