Q.

The resistance of a wire is 10 Ω. Its length is increased by 10% by stretching. The new resistance will now be

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a

12 Ω

b

1.2 Ω

c

13 Ω

d

11 Ω

answer is A.

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Detailed Solution

In case of stretching of wire, R ∝  l2 ⇒ If length is increased by 10% resistance is increased by almost 20% Hence, new resistance R' = 10 + 20% of 10=10  +20100 ×  10=12 Ω
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