A resistance of $$4$$ Ω and a wire of length $$5$$ metres and resistance $$5$$ Ω are joined in series and connected to a cell of e.m.f. $$10$$ V and internal resistance $$1$$ Ω. A parallel combination of two identical cells is balanced across $$300$$ cm of the wire. The e.m.f. E of each cell is

Question

A resistance of $$4$$  Ω and a wire of length $$5$$ metres and resistance $$5$$  Ω are joined in series and connected to a cell of e.m.f. $$10$$ V and internal resistance $$1$$  Ω.  A parallel combination of two identical cells is balanced across $$300$$ cm of the wire. The e.m.f. E of each cell is

Infinity Learn · Accepted Answer

$$E=xl$$ $$=$$  Vl $$=iRL$$ × l  ⇒  $$E=$$ $$eR+Rh$$ $$+r$$ ×  RL  × l⇒  E $$=$$  $$105+4+1$$ ×  $$55$$×  $$3=3$$ V

A resistance of $4 Ω$ and a wire of length 5 metres and resistance $5 Ω$ are joined in series and connected to a cell of e.m.f. 10 V and internal resistance $1 Ω$ . A parallel combination of two identical cells is balanced across 300 cm of the wire. The e.m.f. E of each cell is

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A resistance of 4 Ω and a wire of length 5 metres and resistance 5 Ω are joined in series and connected to a cell of e.m.f. 10 V and internal resistance 1 Ω. A parallel combination of two identical cells is balanced across 300 cm of the wire. The e.m.f. E of each cell is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A resistance of $4 Ω$ and a wire of length 5 metres and resistance $5 Ω$ are joined in series and connected to a cell of e.m.f. 10 V and internal resistance $1 Ω$ . A parallel combination of two identical cells is balanced across 300 cm of the wire. The e.m.f. E of each cell is