The resistance of a wire is 5 ohm at 50°C and 6 ohm at 100°C. The resistance of the wire at 0°C will be

We know thatRt=R0(1+αt)Applying this formula, we get             R50=R0(1+50α)=5        ...(1)and    R100=R0(1+100α)=6        ...(2)Multiplying eq. (1) by 2, we get           2R0(1+50α)=10or         2R0+100α=10               ...(3)Subtracting eq. (2) from eq.(3), we get2R0−R0=10−6=4∴ R0=4Ω