First slide

KVL

Question

The resistances 500 $Ω$ and 1000 $Ω$ are connected in series with a battery of 1.5 volt. The voltage across the 1000 $Ω$ resistance is measured by a voltmeter having a resistance of 1000 $Ω$ . The reading in the voltmeter would be :

Moderate

A

1.5 volt
B

1.0 volt
C

0.75 volt
D

0.5 volt

Solution

Current through battery = $\frac{1.5}{500 + 500} = 1.5 mA$
Voltage drop across 500 $Ω = (1.5 x 10^{- 3}) (500) = 0.75 V$
So reading of voltmeter = 1.5 - 0.75 = 0. 75 V

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App