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The resistances 500 $Ω$ and 1000 $Ω$ are connected in series with a battery of 1.5 volt. The voltage across the 1000 $Ω$ resistance is measured by a voltmeter having a resistance of 1000 $Ω$ . The reading in the voltmeter would be :

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1.5 volt

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0.75 volt

0.5 volt

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detailed solution

Correct option is C

Current through battery = 1.5500+500=1.5 mAVoltage drop across 500 Ω=1.5 x 10-3500=0.75 VSo reading of voltmeter = 1.5 - 0.75 = 0. 75 V

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The resistances 500 Ω and 1000 Ω are connected in series with a battery of 1.5 volt. The voltage across the 1000 Ωresistance is measured by a voltmeter having a resistance of 1000 Ω. The reading in the voltmeter would be :

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Ready to Test Your Skills?

free study material

The resistances 500 $Ω$ and 1000 $Ω$ are connected in series with a battery of 1.5 volt. The voltage across the 1000 $Ω$ resistance is measured by a voltmeter having a resistance of 1000 $Ω$ . The reading in the voltmeter would be :