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Questions  

Resistances of 6 Ω each are connected in the manner shown in fig. With the current 0.5 ampere as

shown in the figure, the potential difference Vp -VQ is

a
3.6 V
b
6.0 V
c
3.0 V
d
7.2 V

detailed solution

Correct option is C

Equivalent resistance R of the three resistances connected in parallel is given by1R′=16+16+16=36=12  or  R′=2ΩThe equivalent resistance R' of the second circuit1R′′=16+112=2+112=14  or  R′′=4ΩThe resistances .R' and R' are connected in series. So, the equivalent resistance of the circuit i'e,, between A and BR= 2+ 4= 6 ΩPotential difference between. A and B=R×i=6×0⋅5=3V

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Similar Questions

Statement 1: Consider the two situations shown in the figure. Potential difference between points A and B in case I is more as compared to case II.

Statement 2: In case I:   VAVB=E+Ir

In case II: VAVB=EIr


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