Resistances of 6 Ω each are connected in the manner shown in fig. With the current 0.5 ampere asshown in the figure, the potential difference Vp -VQ is

Equivalent resistance R of the three resistances connected in parallel is given by1R′=16+16+16=36=12  or  R′=2ΩThe equivalent resistance R' of the second circuit1R′′=16+112=2+112=14  or  R′′=4ΩThe resistances .R' and R' are connected in series. So, the equivalent resistance of the circuit i'e,, between A and BR= 2+ 4= 6 ΩPotential difference between. A and B=R×i=6×0⋅5=3V