First slide

combination of resistance

Question

Resistances of 1, 2 and 3 ohm are connected in the form of a triangle. If a 1.5 volt cell of negligible internal resistance is connected across the 3 ohm resistor, the current flowing through this resistance will be

Moderate

A

0 . 25 amp.
B

0 .5 amp.
C

1 .0 amp
D

1 .5 amp.

Solution

Here 1 and 2 ohm resistances are connected in series Their equivalent resistance is 3 ohm. The total resistance would be a parallel combination of 3 $Ω$ and 3 $Ω$ resistance. This is equal to
$R = \frac{R_{1} R_{2}}{R_{1} + R_{2}} = \frac{3 \times 3}{3 + 3} = \frac{9}{6} = 1 \cdot 5 Ω$
Current flowing through 3 $Ω$ resistance
$= 1 \cdot 5 V / 1 \cdot 5 Ω = 1 \cdot 0 amp$

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