Resistances of 1, 2 and 3 ohm are connected in the form of a triangle. If a 1.5 volt cell of negligible internal resistance is connected across the 3 ohm resistor, the current flowing through this resistance will be

Here 1 and 2 ohm resistances are connected in series Their equivalent resistance is 3 ohm. The total resistance would be a parallel combination of 3Ω and 3Ωresistance. This is equal toR=R1R2R1+R2=3×33+3=96=1⋅5ΩCurrent flowing through 3 Ω resistance=1⋅5V/1⋅5Ω=1⋅0amp