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Resistances R1 and R2, each of 60  Ω, are connected in series as shown in figure. The potential difference between A and B is kept 120 volt. what will be the reading of voltmeter connected between the points C and D if resistance of voltmeter is 120  Ω?

a
48 V
b
24 V
c
40 V
d
None

detailed solution

Correct option is A

R2 and RV are in parallel, their equivalent isR'2 =R2RVR2+RV = 60 × 12060+120  = 40  ΩNow, I =120R1+R'2 =  12060+40  = 1.2 AReading of voltmeter= IR'2=1.2  ×  40=48 V

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