Resistances R1 and R2, each of 60 Ω, are connected in series as shown in figure. The potential difference between A and B is kept 120 volt. what will be the reading of voltmeter connected between the points C and D if resistance of voltmeter is 120 Ω?
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a
48 V
b
24 V
c
40 V
d
None
answer is A.
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Detailed Solution
R2 and RV are in parallel, their equivalent isR'2 =R2RVR2+RV = 60 × 12060+120 = 40 ΩNow, I =120R1+R'2 = 12060+40 = 1.2 AReading of voltmeter= IR'2=1.2 × 40=48 V