First slide

Magnetic field due to a current carrying circular ring

Question

The resistances of three parts of a circular loop are as shown in the figure. The magnetic field at the centre O is

Moderate

A

$\frac{μ_{0} I}{6 a}$
B

$\frac{μ_{0} I}{3 a}$
C

$\frac{3}{2} \frac{μ_{0} I}{a}$
D

zero

Solution

No current will flow through section BC as the potential of point B and C are same, hence magnetic field at centre O will be equal and opposite due to section AB and AC and hence cancel out.

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