The resistances in the two arms of the meter bridge are 5 $Ω$ and R $Ω$ respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6 $l_{1}$ .The resistance R is

Question

Infinity Learn · Accepted Answer

In the first case, At the balance $$point5R=l1100-l$$                              . . . . . (i)In$$ the second case At the balance $$point5(R/2)=1.6l1100-1.6l1$$            . . . . . $$(ii)Divide$$ eqn. $$(i) by eqn. (ii), we get $$12=100-1.6l11.6100-l1160-1.6l1=200-3.2l11.6l1=40$$   or   $$l1=401.6=25$$ cmSubstituting this value in eqn. (i), we get $$5R=2575R=37525$$Ω$$=15$$Ω

The resistances in the two arms of the meter bridge are 5 $Ω$ and R $Ω$ respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6 $l_{1}$ .The resistance R is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The resistances in the two arms of the meter bridge are 5 Ω and R Ω respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l1.The resistance R is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The resistances in the two arms of the meter bridge are 5 $Ω$ and R $Ω$ respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6 $l_{1}$ .The resistance R is