Q.

A resistor develops 500J of thermal energy in 20 s when a current of 1.5A is  passed through it. If the current is increased from 1.5 A to 3 A, what will be the energy developed in 20s.

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a

500 J

b

1500 J

c

2000 J

d

1000 J

answer is C.

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Detailed Solution

I2RT=H ⇒H1H2=I1I22 ⇒H2=500×33/22=2000J
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