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Q.

A resistor and an inductor are connected to an ac supply of 120 V and 50 Hz. The current in the circuit is 3 (A) If the power consumed in the circuit is 108 W, then the resistance in the circuit is

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a

12Ω

b

40Ω

c

(52×28)Ω

d

360Ω

answer is A.

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Detailed Solution

P=irms2.R=32×R 108=9×R⇒R=12Ω

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