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A resistor and an inductor are connected to an ac supply of 120 V and 50 Hz. The current in the circuit is 3 (A) If the power consumed in the circuit is 108 W, then the resistance in the circuit is

a
12Ω
b
40Ω
c
(52×28)Ω
d
360Ω

detailed solution

Correct option is A

P=irms2.R=32×R 108=9×R⇒R=12Ω

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