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Q.

A resistor of 10  kΩhaving tolerance 10% is connected in series with another resistor of 20  kΩ having tolerance 20%. The tolerance of the combination will beapproximately

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a

10%

b

13%

c

17%

d

20%

answer is C.

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Detailed Solution

As, ΔRs=ΔR1+ΔR2=[10100×10+20100×20]kΩ=5  kΩΔRsRs×100=530×100=503=17%
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