Q.
A resistor of 10 kΩhaving tolerance 10% is connected in series with another resistor of 20 kΩ having tolerance 20%. The tolerance of the combination will beapproximately
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a
10%
b
13%
c
17%
d
20%
answer is C.
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Detailed Solution
As, ΔRs=ΔR1+ΔR2=[10100×10+20100×20]kΩ=5 kΩΔRsRs×100=530×100=503=17%
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