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Q.

A resistor R=100Ω is connected in series with a capacitor. A source of supply voltagee=100 cos100πt volt  is connected across the combination. If the current through the circuit is i=42 cos100πt+π4A the value of capacitance is

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a

100πμF

b

50πμF

c

1πμF

d

10πμF

answer is A.

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Detailed Solution

Current leads the supply voltage by an angle ofπ4∴  xcR=tanπ4⇒1/ωcR=1⇒C=1ωR=1100π×100F=100πμF
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