Questions
A resistor R1 dissipates the power P when connected to a certain generator. If a resistor,R2 is put in series with R1, the power dissipated by R1,
detailed solution
Correct option is A
P=V2R∴ P1=V2R1 and P2=V2R1+R2P2Talk to our academic expert!
Similar Questions
A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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