Resolve a weight of 10 N in two directions which are parallel and perpendicular to a slope inclined at 30° to the horizontal.

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53 N and 10 N

53 N and 5 N

53 N and 15 N

53 N and 25 N

answer is B.

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Detailed Solution

Component perpendicular to the planeW⊥=Wcos30°=(10)32=53 Nand component parallel to the planeW‖=Wsin30°=(10)12=5 N

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