First slide

Diffraction

Question

Resolving power of electron microscope is proportional to

Moderate

A

The momentum of the electron
B

Numerical aperture
C

The accelerating potential
D

Both (1) and (2) are right

Solution

de Broglie wave length $λ = \frac{h}{p}$ where p = momentum
Resolving power (R) of electron microscope = $= \frac{2 μ sinθ}{λ} = \frac{2 (μ sinθ)}{h / p}$
$\Rightarrow R = \frac{2 (NA) . p}{h},$
where $μ$ = refractive index of the medium between the object and objective of the microscope, $θ$ is the angle subtended by the radius of the objective at any one object and p is the momentum of electron.

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