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Q.

The resonance frequency of the tank circuit of an oscillator when L=2π2mH and C=0.8μF are connected in parallel is

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a

12.5KHz

b

25KHz

c

1.25KHz

d

2.5KHz

answer is A.

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Detailed Solution

f=12π1LC=12π12π2×10−3×0.8×10−6=12×4×10−5 =0.125×105Hz =12.5KHz

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