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Questions  

The resonance frequency of the tank circuit of an oscillator when L=2π2mH and C=0.8μF are connected in parallel is

a
12.5KHz
b
25KHz
c
1.25KHz
d
2.5KHz

detailed solution

Correct option is A

f=12π1LC=12π12π2×10−3×0.8×10−6=12×4×10−5 =0.125×105Hz =12.5KHz

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