First slide

Transistors

Question

The resonance frequency of the tank circuit of an oscillator when $L = \frac{2}{π^{2}} m H$ and $C = 0.8 μ F$ are connected in parallel is

Moderate

A

12.5KHz
B

25KHz
C

1.25KHz
D

2.5KHz

Solution

$f = \frac{1}{2 π} \sqrt{\frac{1}{L C}} = \frac{1}{2 π} \sqrt{\frac{1}{\frac{2}{π^{2}} \times 10^{- 3} \times 0.8 \times 1 0^{- 6}}} = \frac{1}{2 \times 4 \times 10^{- 5}} = 0.125 \times 10^{5} H z = 12.5 K H z$

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