First slide

Transistors

Question

The resonance frequency of the tank circuit of an oscillator when $L = \frac{10}{π^{2}} m H$ and $C = 0.04 μ F$ are connected in parallel is

Moderate

A

250KHz
B

25 KHz
C

2.5 KHz
D

25MHz

Solution

$\begin{array}{l} f = \frac{1}{2 π} \sqrt{\frac{1}{L C}} \end{array}$
$= \frac{1}{2 π} \sqrt{\frac{1}{\frac{10}{π^{2}} \times 10^{- 3} \times 0.04 \times 10^{- 6}}} = \frac{1}{2 \times 2 \times 10^{- 5}}$
$\begin{array}{l} = 0.25 \times 10^{5} H z \\ = 25 K H z \end{array}$

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