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The resonance frequency of the tank circuit of an oscillator when $L = \frac{10}{π^{2}} m H$ and $C = 0.04 μ F$ are connected in parallel is

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250KHz

25 KHz

2.5 KHz

25MHz

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detailed solution

Correct option is B

f=12π1LC =12π110π2×10−3×0.04×10−6=12×2×10−5=0.25×105Hz=25KHz

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The resonance frequency of the tank circuit of an oscillator when L=10π2mH and C=0.04μF are connected in parallel is

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Ready to Test Your Skills?

free study material

The resonance frequency of the tank circuit of an oscillator when $L = \frac{10}{π^{2}} m H$ and $C = 0.04 μ F$ are connected in parallel is