Q.

In a resonance pipe the first and second resonances are obtained at depths 22.7 cm and 70.2 cm respectively. What will be the end correction

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a

1.05 cm

b

115.5 cm

c

92.5 cm

d

113.5 cm

answer is A.

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Detailed Solution

For end correction x,  l2+xl1+x=3λ/4λ/4=3x=l2−3l12=70.2−3×22.72=1.05 cm
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