Questions
In resonance tube experiment, a closed organ pipe of length 124 cm resonates when activated by a tuning fork of frequency 340 Hz. If more water is poured in the pipe then [speed of sound in air is 340 ]
detailed solution
Correct option is B
Wavelength =340340=1 mIdeal resonating lengths are 14m, 34m, 54m, ...For fifth harmonic to occur, total vibrating length should be 1.25 m.∴ end correction = e = 1.25-1.24 = 0.01 m = 1 cmSo, e = 1 cm = 0.3 d(diameter) d = 3.3 cmThe minimum finite length of water column to have resonance = 1.25 - 0.75 = 0.5 mHence minimum length of air column = 0.25 – 0.01 m = 0.24 m = 24 cmThe difference between two successive readings at resonances = 74 cm - 24 cm = 50 cmTalk to our academic expert!
Similar Questions
An organ pipe P1 closed at one end vibrating in its first overtone and another pipe P2 open at the both ends vibrating in its third overtone are in resonance with a given tuning fork. The ratio of the length of P1 to that of P2 is then n = ?
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