Questions
In a resonance tube experiment, the first two resonances are observed at length 10.5 crn and 29.5 cm. The third resonance is observed at the length __(cm).
detailed solution
Correct option is C
λ2 = l2-l1 = 29.5-10.5 = 19 cmThird resonance will be observed atl3 = l2+λ2 = 29.5 + 19 = 48.5 cmTalk to our academic expert!
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