First slide

Experiments to find speed of sound

Question

In a resonance tube experiment, the first two resonances are observed at length 10.5 crn and 29.5 cm. The third resonance is observed at the length __(cm).

Moderate

A

47.5
B

58.5
C

48.5
D

82.8

Solution

$\frac{λ}{2} = l_{2} - l_{1} = 29.5 - 10.5 = 19 cm$
Third resonance will be observed at
$l_{3} = l_{2} + \frac{λ}{2} = 29.5 + 19 = 48.5 cm$

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