First slide

Stationary waves

Question

In a resonance tube experiment when the tube is filled with water up to a height of 17.0 cm from bottom, it resonates with a given tuning fork . When the level is raised the next resonance with the same tuning fork occurs at a height of 24.5 cm . If the velocity of sound in air is 330 m/s , the tuning fork frequency is :

Moderate

A

1100Hz
B

550Hz
C

2200Hz
D

3300Hz

Solution

$\begin{array}{l} {For two consecutive resonance, L}_{2} {-L}_{1} = \frac{λ}{2} \\ \Rightarrow 24.5 - 17 = \frac{λ}{2} \\ \begin{array}{l} \Rightarrow λ = 15cm \\ W e k n o w, f = \frac{v}{λ} \\ \Rightarrow f = \frac{330}{15 (10^{- 2})} = 2200 H z \end{array} \end{array}$

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