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Q.

In a resonance tube the first resonance with a tuning fork occurs at 16 cm and second at 49 cm. If the velocity of sound is 330 m/s, the frequency of tuning fork is (in Hz)

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a

500

b

300

c

330

d

165

answer is A.

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Detailed Solution

For closed pipe l1=v4n; l2=3v4n⇒v=2n (l2−l1)⇒n=v2(l2−l1)=3302×(0.49−0.16)=500 Hz
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