Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

In a resonance tube, using a tuning fork of frequency 325 Hz, two successive resonance lengths are observed at 25. 4 cm and 77 . 4 cm respectively. Thevelocity of sound in air is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

338 ms-1

b

328 m s-1

c

330 m s-1

d

320 m s -1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

l1 +x=λ/4  and  l2 + x=3λ4 where x is the end correction . l2−l1=λ2  or  Î»=2l2−l1 or Î»=2(77⋅4−25⋅4) Î»=104cm V=nλ=325×104=33800cm/s=338m/s
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring