Rest mass energy of a particle is 3 MeV and the particle is moving with a linear momentum of 2.133×10−21 Kg−m/s. Then total energy of the particle is

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6 MeV

8 MeV

5 MeV

4 MeV

answer is C.

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Detailed Solution

Total energy is given by E2=moc2+pc2Now, moc2=3 MeVpc=2.133×10−21×3×1081.6×10−19×106MeV=4 MeV∴ E=32+42 MeV=5 MeV

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