Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 2° is(g=10m/s-2)
0.017 N
1.7 N
0.17 N
0.0348 N
restoring force = FR=mgsinθm=mass of oscillator, g=acceleration due to gravityif θ is very small, then sinθ≃θthen FR=mgθ FR=100(10-3)10(20) FR=2π180 FR=2×3.14180 FR=0.0348N