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Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 2° is(g=10m/ $s^{- 2}$ )

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0.017 N

1.7 N

0.17 N

0.0348 N

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detailed solution

Correct option is D

restoring force = FR=mgsinθm=mass of oscillator, g=acceleration due to gravityif θ is very small, then sinθ≃θthen FR=mgθ FR=100(10-3)10(20) FR=2π180 FR=2×3.14180 FR=0.0348N

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Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 2° is(g=10m/s-2)

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Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 2° is(g=10m/ $s^{- 2}$ )