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Q.

Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 1° is (here acceleration due to gravity =10ms-2)

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a

0.017 N

b

1.7 N

c

0.17 N

d

0.034 N

answer is A.

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Detailed Solution

Restoring force on simple pendulum=  FR=mgsinθ here θ is very small, hence sinθ≃θ ⇒ FR=mgθ            =100×10-3×10×1∘,here 1∘=π180,substitute            =10001000×π180  ⇒ FR=3.14180=0.017 N
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