Q.
Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 1° is (here acceleration due to gravity =10ms-2)
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a
0.017 N
b
1.7 N
c
0.17 N
d
0.034 N
answer is A.
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Detailed Solution
Restoring force on simple pendulum= FR=mgsinθ here θ is very small, hence sinθ≃θ ⇒ FR=mgθ =100×10-3×10×1∘,here 1∘=π180,substitute =10001000×π180 ⇒ FR=3.14180=0.017 N
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