Questions
Restoring force on the bob of a simple pendulum of mass 100 g when its amplitude is 1° is (here acceleration due to gravity =10m)
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Correct option is A
Restoring force on simple pendulum= FR=mgsinθ here θ is very small, hence sinθ≃θ ⇒ FR=mgθ =100×10-3×10×1∘,here 1∘=π180,substitute =10001000×π180 ⇒ FR=3.14180=0.017 NSimilar Questions
A simple pendulum is hanging from a peg inserted in a vertical wall. Its bob is stretched in horizontal position from the wall and is left free to move. The bob hits on the wall the coefficient of restitution is . After how many collisions the amplitude of vibration will become less than 60°
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