First slide

Accuracy; precision of instruments and errors in measurements

Question

The result after adding $3.8 \times 10^{- 6} t o 4.2 \times 10^{- 5}$ with due regard to significant figures is

Moderate

A

$4.58 \times 10^{- 5}$
B

$0.458 \times 10^{- 4}$
C

$4.6 \times 10^{- 5}$
D

$45.8 \times 10^{- 6}$

Solution

$3.8 \times 10^{- 6} + 4.2 \times 10^{- 5}$
$= (3.8 \times 10^{- 1} + 4.2) \times 10^{- 5}$
$= (0.38 + 4.2) \times 10^{- 5}$
$= (4.58) \times 10^{- 5}$
Rounding off to one place of decimal.
The sum $= 4.6 \times 10^{- 5}$

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