The resultant of A→+B→ is R→1 . On reversing the vector B→ the resultant becomes R→2. What is the value of R12+R22 ?
A2+B2
A2−B2
2A2+B2
2A2−B2
R→1=A→+B→,R→2=A→−B→∴R12+R22=A2+B2+2ABcosθ2+A2+B2-2ABcosθ2=2A2+B2