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Q.

The resultant of A→+B→ is R→1 . On reversing the vector B→ the resultant becomes R→2. What is the value of R12+R22 ?

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a

A2+B2

b

A2−B2

c

2A2+B2

d

2A2−B2

answer is C.

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Detailed Solution

R→1=A→+B→,R→2=A→−B→∴R12+R22=A2+B2+2ABcosθ2+A2+B2-2ABcosθ2=2A2+B2
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The resultant of A→+B→ is R→1 . On reversing the vector B→ the resultant becomes R→2. What is the value of R12+R22 ?