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The resultant of $\vec{A} + \vec{B}$ is ${\vec{R}}_{1}$ . On reversing the vector $\vec{B}$ the resultant becomes ${\vec{R}}_{2}$ . What is the value of $R_{1}^{2} + R_{2}^{2}$ ?

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A2+B2

A2−B2

2A2+B2

2A2−B2

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detailed solution

Correct option is C

R→1=A→+B→,R→2=A→−B→∴R12+R22=A2+B2+2ABcosθ2+A2+B2-2ABcosθ2=2A2+B2

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The resultant of A→+B→ is R→1 . On reversing the vector B→ the resultant becomes R→2. What is the value of R12+R22 ?

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The resultant of $\vec{A} + \vec{B}$ is ${\vec{R}}_{1}$ . On reversing the vector $\vec{B}$ the resultant becomes ${\vec{R}}_{2}$ . What is the value of $R_{1}^{2} + R_{2}^{2}$ ?