First slide

The Electrostatic analog

Question

The resultant magnetic moment for the following arrangement is (the vectors are non coplanar)

Moderate

A

M
B

2M
C

3M
D

4M

Solution

$\begin{array}{rcl} M' & = & \sqrt{4 M^{2} + 4 M^{2} + 2.2 M . 2 M \cos 120^{o}} (∵ \cos 120^{o} = - \frac{1}{2}) \\ M' & = & \sqrt{8 M^{2} - 4 M^{2}} = \sqrt{4 M^{2}} = 2 M \end{array}$

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