The resultant of two forces 1 and P is perpendicular to ‘1’ and equal to 1. What is the value of ‘P’ and angle between the forces

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√2 N, 1350

√2 N, 1500

2 N , 1200

2 N , 1500

answer is A.

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Detailed Solution

In magnitude12 + 12 = P2P = √2 NTanθ = 1/1 = 1 = Tan450 ⇒ θ = 450;The angle between the forces = θ + 900 ⇒ 450 + 900 ⇒ 1350

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