Q.
The resultant of two forces 1 and P is perpendicular to ‘1’ and equal to 1. What is the value of ‘P’ and angle between the forces
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a
√2 N, 1350
b
√2 N, 1500
c
2 N , 1200
d
2 N , 1500
answer is A.
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Detailed Solution
In magnitude12 + 12 = P2P = √2 NTanθ = 1/1 = 1 = Tan450 ⇒ θ = 450;The angle between the forces = θ + 900 ⇒ 450 + 900 ⇒ 1350
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