Questions
The resultant of two rectangular simple harmonic motions and of the same frequency and unequal amplitudes but differing in phase by is
detailed solution
Correct option is C
Let us consider two simple harmonic motion y=bsinωt ……………………..(1)x=asinωt+ϕ ………………………(2)x=asinωtcosϕ+acosωtsinϕ From (1) yb=sinωt and 1−y2b2=cos ωtSubstituting these is equation (2) we get xa=ybcosϕ+1−y2b2sinϕ Taking square on both sides we get xa−ybcosϕ2=1−y2b2sinϕ2 Thus xa2+yb2cos2ϕ−2xyabcosϕ=1−y2b2sin2ϕSimplifying this we getxa2+yb2−2xyabcosϕ=sin2ϕIn this case ϕ=π2Making the equation an ellipseTalk to our academic expert!
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A particle is moving in a circle with uniform speed. Its motion is
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