Questions
The resultant of two vectors A and B is perpendicular to vector A and its magnitude is equal to half of the magnitude of vector B, The angle between A and B is
detailed solution
Correct option is B
Here (A+B)⋅A=0A2+ABcosθ=0or ABcosθ=−A2....(1)Bcosθ=−A...(2)Further, |A+B|=12|B|or (A+B)⋅(A+B)=12|B|2A2+B2+2ABcosθ=14B2or A2+ABcosθ+B2+ABcosθ=14B20+B2+ABcosθ=−14B2or ABcosθ=−34B2 …(3)From eqs. (1) and (3)A2=34B2 or A=(3/2)BFrom eq. (2), Bcosθ=−(3/2)Bor cosθ=−3/2 or θ=150∘Similar Questions
The resultant of A and B makes an angle with A and with B, then
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