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The resultant of two vectors $\vec{A}$ of magnitude $2$ units and $\vec{B}$ of magnitude 1 unit is $\vec{C}$ . If angle between $\vec{A}$ and $\vec{B}$ is $60^{0}$ , then what is the angle between resultant and $\vec{B}$

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detailed solution

Correct option is A

The angle between resultant C→ and B→ istanβ=A sinθB+A cosθ=2 sin6001+2 cos600=32β=tan-132

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The resultant of two vectors A→ of magnitude 2 units and B→ of magnitude 1 unit is C→. If angle between A→ and B→ is 600, then what is the angle between resultant and B→

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The resultant of two vectors $\vec{A}$ of magnitude $2$ units and $\vec{B}$ of magnitude 1 unit is $\vec{C}$ . If angle between $\vec{A}$ and $\vec{B}$ is $60^{0}$ , then what is the angle between resultant and $\vec{B}$