First slide

Motion in a plane

Question

Resultant of two vectors of magnitudes P and Q is of magnitude ‘Q’. If the magnitude of $\large \vec Q$ is doubled now the angle made by new resultant with $\large \vec P$ is

Moderate

A

30⁰
B

90⁰
C

60⁰
D

120⁰

Solution

$R = \sqrt {{P^2} + {Q^2} + 2PQ\cos \theta } = Q$
$\Rightarrow {Q^2} = {P^2} + {Q^2} + 2PQ\cos \theta$

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