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Questions  

The resultant of two vectors P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then, R equal to

a
P
b
(P+Q)
c
Q
d
(P-Q)

detailed solution

Correct option is C

We have, 2Q sinθ = P, as R⊥PNow, R=P2+Q2+2PQcos90°+θ=P2+Q2-2PQsinθ=(2Qsinθ)2+Q2-2(2Qsinθ)Qsinθ=4Q2sin2θ+Q2-4Q2sin2θ=Q

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