The resultant of vectors A and B is R1 . On reversing the direction of vector B, the resultant becomes R2.What is the value of R12 + R22 ?
A2 + B2
A2 - B2
2(A2 + B2)
2 (A2 - B2)
We have,R12 = A2+B2+2AB cos θand R22 = A2+B2+2AB cos θ∴ R12+ R22 = 2(A2+B2)