The resultant of vectors A and B is R1 . On reversing the direction of vector B, the resultant becomes R2.What is the value of R12 + R22 ?

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A2 + B2

A2 - B2

2(A2 + B2)

2 (A2 - B2)

answer is C.

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Detailed Solution

We have,R12 = A2+B2+2AB cos θand R22 = A2+B2+2AB cos θ∴ R12+ R22 = 2(A2+B2)

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