Q.

The resultant of vectors A and B is R1 . On reversing the direction of vector B, the resultant becomes R2.What is the value of R12  + R22 ?

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a

A2 + B2

b

A2 - B2

c

2(A2 + B2)

d

2 (A2 - B2)

answer is C.

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Detailed Solution

We have,R12   =  A2+B2+2AB cos θand R22   =  A2+B2+2AB cos θ∴   R12+ R22   =  2(A2+B2)
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