First slide

Diodes

Question

The reverse bias in a junction diode is changed from 8 V to 13 V, then the value of the current changes from 40μA to 60μA. The resistance of junction diode will be

Easy

A

$2 x 10^{5} Ω$
B

$2.5 x 10^{5} Ω$
C

$3 x 10^{5} Ω$
D

$4 x 10^{5} Ω$

Solution

$D y n a m i c R e s i s \tan c e R = \frac{△ V}{△ I} = \frac{(13 - 8)}{(60 - 40) \times 10^{- 6}} = \frac{5 \times 10^{6}}{20} = 2.5 \times 10^{5} Ω$

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