A reversible adiabatic path on a $$P-V$$ diagram for an ideal gas passes through state A where $$P=0.7$$×$$105N/m$$−$$2and$$ $$v=0.0049$$ $$m3$$. The ratio of specific heat of the gas is $$1.4$$. The slope of path at A is

Correct option is 3−2.0×107Nm−5

Questions

A reversible adiabatic path on a P-V diagram for an ideal gas passes through state A where $P = 0.7 \times 10^{5} N / m^{- 2}$ and $v = 0.0049 m^{3}$ . The ratio of specific heat of the gas is 1.4. The slope of path at A is

Remember concepts with our Masterclasses.

80k Users

60 mins Expert Faculty Ask Questions

2.0×107Nm−5

1.0×107Nm−5

−2.0×107Nm−5

−1.0×107Nm−5

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

PVγ=constVγdPdV+γ PVγ−1dVdV=0dPdV=γ PVγ−1Vγ=−γPV=−1.4×.7×105.0049=−2×107

Talk to our academic expert!

Create Your Own Test
Your Topic, Your Difficulty, Your Pace

Similar Questions

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure $P_{1} = 10^{5} P a$ and volume $V_{i} = 10^{- 3} m^{3}$ changes to final state at $P_{f} = \frac{1}{32} \times 10^{5} p a & V_{f} = 8 \times 10^{- 3} m^{3}$ in an adiabatic quasi-static process, such that $P^{3} V^{5} =$ constant. Consider another thermodynamic process that brings the system form the same initial state to the same final state in two steps: an isobaric expansion at $P_{i}$ followed by an isochoric (is volumetric) process at volume $V_{f}$ . The amount of heat supplied to the system in the two-step process is approximately