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A reversible engine converts one-sixth of the heat input into work. When the temperature of the sink is reduced by
detailed solution
Correct option is D
Initially, η=1−T2T1=16---(1) Finally, 2η=1−T2−62T1 2η=1−T2T1+62T1 2η=η+62T1 16=62T1 T1=372K=990C substitute in (1) we get T2=310K=370CSimilar Questions
One of the most efficient engines ever developed operates between 2100 K and 700 K. Its actual efficiency is 40%. What percentage of its maximum possible efficiency is this?
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