First slide

Projection Under uniform Acceleration

Question

A rifle shoots a bullet with a muzzle velocity of 400 ms^-1 at a small target 400 m away. The height above the target at which the bullet must be aimed to hit the target is (g = 10 ms^-2).

Moderate

A

1 m
B

5 m
C

10 m
D

0.5 m

Solution

Time taken by bullet to reach the target is
$\frac{Distance}{velocity} = \frac{Distance}{ucos θ} [As θ is very small, \cos θ = 1] Time = \frac{Distance}{u} = \frac{400}{400} = 1 s Vertical deflection of bullet is = \frac{1}{2} {gt}^{2} = \frac{1}{2} \times 10 \times (1)^{2} = 5 m$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App