Q.
A right angled triangular loop as shown below enters uniform magnetic field (at right angle to the boundary of the field) directed into the paper. Draw the graph between induced emf e and the distance along the perpendicular to the boundary of the field, (say x) along which loop moves.
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
b
c
d
answer is C.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
For 0≤x≤a, ϕ=12Bx2 e=-dϕdt=-Bav At x=0,e=0 At x=a/2, e=-Bav2 At x=x→a,e≈-Bav As x=a,e=0 ϕ=constant For a≤x≤2a ϕ=12Ba2=constant For 2a≤x≤3a, ϕ=Ba22-x122 e=-dϕdt=-ddtB2a2-x12=Bx1v At x1=0, e=0 At x1=a/2,e=B2avAt x1=a,e=0, loop is outside the field.
Watch 3-min video & get full concept clarity