A right angled triangular loop (as shown in the figure) enters into uniform magnetic field (at right angle to the boundary of the field) directed into the paper. Theloop moves always with constant speed. Draw the graph between induced emf e and the distance along the perpendicular to the boundary of the field (say x) alongwhich loop moves.
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answer is C.
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Detailed Solution
For 0≤x≤a The flux enclosed ϕ=12Bx2 Hence induced emf, e=−dϕdt=−Bxv At x=0, e=0 At x=a2, e=−Bav2 At x=a, e=−BavNow considering for a