Questions
A right angled triangular loop (as shown in the figure) enters into uniform magnetic field (at right angle to the boundary of the field) directed into the paper. The
loop moves always with constant speed. Draw the graph between induced emf e and the distance along the perpendicular to the boundary of the field (say x) along
which loop moves.
detailed solution
Correct option is C
For 0≤x≤a The flux enclosed ϕ=12Bx2 Hence induced emf, e=−dϕdt=−Bxv At x=0, e=0 At x=a2, e=−Bav2 At x=a, e=−BavNow considering for aTalk to our academic expert!
Similar Questions
A square wire loop, of side a has a long straight wire carrying a constant current i that passes through the centre of the loop and perpendicular to its plane as shown in Fig.
The current induced in the square loop is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests