To the right of line PQ is a uniform magnetic field B. $$B1A$$ is the line of incidence of a charged particle, which comes out of the field along DE; CA and DF are the normals at A and D. $$B1AC$$ $$=$$ θ. Angle measured from CA in clockwise direction is taken as positive. The maximum range of movement of the centre of the part of the circle from line AD in which charged particle of charge Q moves with a velocity v whenθ is positive to when θ is negative is given by

Question

To the right of line PQ is a uniform magnetic field B. $$B1A$$ is the line of incidence of a charged particle, which comes out of the field along DE; CA and DF are the normals at A and D. $$B1AC$$ $$=$$ θ. Angle measured from CA in clockwise direction is taken as positive. The maximum range of movement of the centre of the part of the circle from line AD in which charged particle of charge Q moves with a velocity v whenθ is positive to when θ is negative is given by

Infinity Learn · Accepted Answer

An observation will show that when θ is positive and actually $$900$$, angle formed will be $$2$$π at the centre and centre of the circle formed by the charged particle will be at a distance of radius of the circle from AD. It will be also true for θ to be negative. $$($$θ measured anticlockwise from normal $$AC)$$ Hence range is ±$$r=$$±mvQB

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