First slide

Second law

Question

A rigid ball of mass $m$ strikes a rigid wall at $60^{0}$ and gets reflected without loss of speed as shown in the figure. The value of impulse imparted by the wall on the ball will be

Easy

A

mv
B

2mv
C

$\frac{m v}{2}$
D

$\frac{m v}{3}$

Solution

As we know Impulse = Change in momentum. Now along the wall there is no change momentum. The change in momentum perpendicular to the wall is $m v C o s 60^{0} - (- m v C o s 60^{0}) = 2 m v C o s 60^{0} = m v$

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