First slide

laws

Question

A rigid container contains helium gas at 150 KPa and $127^{o} C$ . If $R = 8.3 J - m o l^{- 1} K^{- 1}$ , the density of the gas is

Moderate

A

$1.2 \times 10^{- 2} k g / m^{3}$
B

$0.8 \times 10^{- 1} k g / m^{3}$
C

$0.18 k g / m^{3}$
D

$0.06 k g / m^{3}$

Solution

$P V = n R T \Rightarrow P = (\frac{m}{V}) . \frac{R T}{M} P = \frac{ρ R T}{M} \Rightarrow ρ = \frac{P M}{R T}$
$\begin{array}{l} ∴ ρ = \frac{150 \times 10^{3} \times 4 \times 10^{- 3}}{8.3 \times 400} k g / m^{3} = 0.18 k g / m^{3} \end{array}$

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