A rigid container contains some ideal gas. Mean free path of the molecules is λ. If temperature of the gas is now doubled, mean free path of the molecules will be
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a
2 λ
b
4 λ
c
6 λ
d
λ
answer is D.
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Detailed Solution
Mean free path λ=12πd2xwhere d= diameter of molecule and n = Number of molecules per unit volume.Since the volume of the container remains uncharged, ‘n’ remains unchanged and hence mean free path remains unchanged.