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Q.

A rigid container contains some ideal gas. Mean free path of the molecules is λ. If temperature of the gas is now doubled, mean free path of the molecules will be

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a

2 λ

b

4 λ

c

6 λ

d

λ

answer is D.

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Detailed Solution

Mean free path λ=12πd2xwhere d= diameter of molecule and n = Number of molecules per unit volume.Since the volume of the container remains uncharged, ‘n’ remains unchanged and hence mean free path remains unchanged.
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