A rigid container with thermally insulated walls contains a coil resistance   100Ω carrying current 1 A change in internal energy after 5 minutes will be

work done(dW) = heat energy produced in the resistordW=dU=change in internal energy  heat energy produced in a resistor is dW=i2Rtgiven current i=1A;resistance R=100Ω;time t=5x60=300s   substitute given values in above equationheat energy produced in a resistor =1×100×300 ⇒change in internal energy =30000J ⇒change in internal energy = 30 kJ