A rigid uniform bar AB of length L slipping from its vertical position on a frictionless floor (as shown in the figure). At some instant of time, the angle made by the bar with the vertical is θ . Which of the following statements about its motion is/are correct?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Instantaneous torque about the point in contact with the floor is proportional to sinθ

The trajectory of the point A is a parabola

The midpoint of the bar will fall vertically downward

When the bar makes an angle θ with the vertical, the displacement of its midpoint from the initial position is proportional to 1−cosθ.

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

rB=mgℓ2sin⁡θ⇒ Option [A] is correct. [B] Coordinates of point A , x=L2sin⁡θ and y=Lcos⁡θ⇒2xL2+yL2=1 This represents ellipse. Since, there is no external force in horizontal direction, option [C] is correct. ΔXcom=ℓ2−ℓ2cos⁡θ=ℓ2(1−cos⁡θ)⇒ Option [D] is correct.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th